At room temperature, the element bromine is a liquid with a density of 3.12 g/mL. a Calculate the mass of 542 mL of bromine.
Mass = blank g
b What volume does 60.0 g of bromine occupy?
Volume =
mL

The answer to both solution is as follows:-

All the data is given in the question,

The formula we will use is as follows:-

 = 1691.04 g

Hence, the mass of the bromine is 1691.04g

The volume of bromine =

The volume of bromine is 19.23mL.

Hence, the mass and the volume are 1691.4g and 19.23ml.

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A. 1691.04 g

B. 19.23 mL

Explanation:

The following data were obtained from the question:

Density of bromine = 3.12 g/mL.

A. Determination of the mass of bromine.

Density of bromine = 3.12 g/mL.

Volume of bromine = 542 mL

Mass of bromine =?

Density = mass /volume

3.12 = mass /542

Cross multiply

Mass of bromine = 3.12 × 542

Mass of bromine = 1691.04 g

B. Determination of of volume of bromine.

Density of bromine = 3.12 g/mL.

Mass of bromine = 60 g

Volume of bromine =...?

Density = mass /volume

3.12 = 60 / volume

Cross multiply

3.12 × volume = 60

Divide both side by 3.12

Volume of bromine = 60/3.12

Volume of bromine = 19.23 mL.

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.

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