Complete these equations for the ionization of an arrhenius acid or base in water. include the states of the products.. 1.) hi(aq). 2.) lioh(s)

To complete these equations for the ionization of an Arrhenius acid or base in water, here is my answer. 

For the first equation, HI(aq), that would be H3O + (aq) + I - (aq)

For the second equation, LiOH(s), it would be Li + (aq) + OH - (aq)

Hope this helps your homework.

The answer would be

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer