How many grams of 02 are needed to completely burn 26.2 g of c3h8

We need 95.0 grams of O2

Explanation:

Step 1 :Data given

Mass of C3H8 = 26.2 grams

Molar mass C3H8  = 44.1 g/mol

Step 2: The balanced equation

C3H8 + 5O2 → 3CO2 + 4H2O

Step 3: Calculate moles C3H8

Moles propane = mass / molar mass

Moles propane = 26.2 grams / 44.1 g/mol

Moles propane = 0.594 moles

Step 4: Calculate moles O2

For 1 mol propane we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O

For 0.594 moles propane we need 5*0.594 = 2.97 moles O2

Step 5: Calculate mass O2

Mass O2 = moles * molar mass

Mass O2 = 2.97 moles * 32.0 g/mol

Mass O2 = 95.0 grams

We need 95.0 grams of O2

a. hope i'm right

explanation: