How many NH4+ ions are there in 2.5 moles of (NH4)3PO4

45.165× 10²³ NH₄⁺ ions

Explanation:

Given data:

Number of NH₄⁺ ions present = ?

Moles of (NH₄)₃PO₄ = 2.5 mol

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole of  (NH₄)₃PO₄   = 3 mole NH₄⁺  

In 2.5 moles of  (NH₄)₃PO₄ = 2.5× 3 = 7.5 moles of NH₄⁺

Number of ions of NH₄⁺ in 2.5 moles of  (NH₄)₃PO₄:

7.5 mole of NH₄⁺  × 6.022 × 10²³ NH₄⁺ ions / 1 mol

45.165× 10²³ NH₄⁺ ions

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa