A rod of iron of uniform density has a thickness such that a one-inch-long segment of it weighs 3.88 ounces. Given that there are 0.035273 ounces in a gram and 2.54 centimeters in an inch, how many grams would a 14.79 cm length of the same iron rod weigh?

Weight of 14.79 cm rod of iron = 640.51 gram (Approx)

Explanation:

Given:

Weight of 1 inch rod = 3.88 ounce

1 inch = 2.54 centimetre

1 gram = 0.035273 ounce

Find:

Weight of 14.79 cm rod of iron

Computation:

Weight of 14.79 cm rod of iron = 14.79[3.88/{(0.035273)(2.54)}]

Weight of 14.79 cm rod of iron = 57.3852 / 0.08959342

Weight of 14.79 cm rod of iron = 640.5068

Weight of 14.79 cm rod of iron = 640.51 gram (Approx)

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it's c. elements are placed in rows based on how may valencies electrons have.