How many moles of HCl are present in 75.0 mL of a 0.200 M
solution?

0.015 mol HCL

Explanation:

Molarity = moles solute/liters solution

Step 1: Define variables

M = 0.200

L = 75.0 mL

m = unknown, x

Step 2: Convert mL to L

1000 mL = 1 L

75.0 mL/1000 mL = 0.075 L

Step 3: Substitute

0.200 M = x mol/0.075 L

Step 4: Find x

x = 0.015 mol HCL

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.