Which of the following solutions would have the smallest freezing point depression at the same temperature? A. 1.0 M NaCl
B. 2.0 M NaCl
C. 3.0 M NaCl
D. 4.0 M NaCl

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

hloride, what is the mass of calcium in

explanation:

they are both synthetic elements

explanation:

d

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