Complete each nuclear fission reaction. 2351
92
3U + 'n → Kr+Ba+3 'n
2. Pu+ 'n → Ba + "Sr+3 'n
A:
B:
00
C:

i think the answer is terrae but not 100 percent sure. ▓▬▬ §

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally