A newspaper article about the danger of global warming from the accumulation of greenhouse gases such as carbon dioxide states that "reducing driving your car by 20 miles a week would prevent release of over 1000 pounds of CO 2 per year into the atmosphere." Is this a reasonable statement? Assume that gasoline is octane (molecular formula is C 8 H 18 ) and that it is burned completely to CO 2 and H 2 O in the engine of your car. Facts (or reasonable guesses) about your car's gas mileage, the density of octane, and other factors will also be needed.

Mass of CO2 produced = 944.43 -lb/year

Since 944.43 -lb is close to 1000 -lb, it is a reasonable statement.

Explanation:

Assumptions:

Car mileage = 20 miles/gallon:

Density of gasoline = 0.702 g/ml

Volume of gallons per week = (20 miles/week) / (20 miles/gallon) = 1 gallon/week

Volume of gasoline per year = 52 weeks * 1 gallon/week = 52 gallons

1 gallon = 3.8 litres or 3800 ml

52 gallons = 52 * 3800 = 197600 ml

Mass of gasoline = volume *density

Mass of gasoline = 197600 ml * 0.702 g/ml

Mass of gasoline = 138715.2 g

Equation of reaction:

2C8H18 + 25O2 ---> 16CO2 + 18H2O

2 moles of octane produces 16 moles of CO2

Molar mass of octane = 114 g/mol; molar mass of CO2 = 44 g/mol

114 * 2 g of octane = 44 * 16 g of CO2

138715. 2 g of octane produces = (138715.2 * 44 * 16) / 114 * 2 of CO2

Mass of CO2 produced = 428313.6 g of CO2 = 428.3136 Kg

Mass of CO2 produced in -lb weight = 428.3136 * 2.205

Mass of CO2 produced per year = 944.43 -lb CO2

Since 944.43-lb is close to 1000 -lb, therefore, it is a reasonable statement.

the ozone layer acts as a filter for the shorter wavelength and highly hazardous ultraviolet radiation (uvr) from the sun, protecting life on earth from its potentially harmful effects. when the sky is clear, there is an inverse relationship between stratospheric ozone and solar uvr measured at the earth's surface.

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