A certain sample of a gas has a volume of 20 L at 0 oC and 1 atm. A plot of the experimental data of its volume against the Celsius temperature, θ, at constant P, gives a straight line of slope 0.0741 L(C)^-1. From these data alone (without making use of the perfect gas law), determine the absolute zero of temperature in degrees Celsius.

The absolute zero temperature T = - 269.91° C

Explanation:

From the given information:

The plot of the volume of the experimental data against the celsius temperature can be expressed mathematically as:

V = mT + c

V = 0.0741 × T+c --- (1)

where;

m, which is the straight line of the slope = 0.0741

replacing the value of V to be = 20 L, T= 0.

Then:

20 = 0.0741 × 0 + c

20 = c

From equation (1), replacing the value of c with 20, we have:

V = 0.0741 × T+20

SO, to determine absolute zero temperature: we have the volume to be zero at absolute zero temperature, Thus:

0 = 0.0741 × T+20

0.0741 T + 20  = 0

0.0741 T = - 20

T = - 269.91° C

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"