If you have a 437 g sample of a mineral that has a density of 1.874 g/mL, what is the volume of your sample of the mineral

233 mL.

Explanation:

The formula you have to use for this problem is Density = Mass/Volume. Just plug in the relevant values. In this case, it would be 1.874 g/mL = 437 g/Volume. Then just divide both sides by 1.874 g/mL, and multiply both sides by Volume. Then you get the following:

Volume = 437 g. / 1.874 g./mL

which can also be written as:

Volume = 437 g. x (1 mL. / 1.874 g.)

Using dimensional analysis, we can cancel out the grams and the product should have 3 sig fig.'s according to sig fig. rules. This gives us an answer of 233 mL.

Cheers.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but