What is the length (in cm) of the side of an iron ingot (rectangular box) that has a mass of 4.578 kg and has width = height = 5.00 cm
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Answer : The length of the side of an iron ingot (rectangular box) is 0.0233 cm.

Explanation : Given,

Width of rectangular box = 5.00 cm

Height of rectangular box = 5.00 cm

Mass of rectangular box = 4.578 g

Density of iron =

First we have to determine the volume of rectangular box.

Formula used :

Now we have to determine the length of rectangular box.

Formula for volume of rectangle :

where,

V = volume of rectangular box

l = length of rectangular box

b = width of rectangular box

h = height of rectangular box

Now put all the given values in the above formula, we get:

Therefore, the length of the side of an iron ingot (rectangular box) is 0.0233 cm.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.