Compounds A and B are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 g of sulfur with 5.99 g of oxygen, and compound B results from combining 8.60 g of sulfur with 12.88 g of oxygen. Show that the mass ratios in the two compounds are simple multiples of each other.

1.5

Explanation:

Given that :

Compound A and B are formed from Sulfur + Oxygen.

Compound A :

6g sulfur + 5.99g Oxygen

Compound B:

8.6g sulfur + 12.88g oxygen

Comparing the ratios :

Compound A:

S : O = 6.00 : 5.99

S/0 = 6.0g S / 5.99g O

Compound B :

S : O = 8.60 : 12.88

S / O = 8.60g S / 12.88g O

Mass Ratio of A / mass Ratio of B

(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)

(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)

(6 × 12.88) / (5.99 × 8.60)

= 77.28 / 51.514

= 1.50017

= 1.5

answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

= enthaply

= energy of products

= energy of reactants

as , thus comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be