The density of water at 40°C is 0.992 g/mL. What is the volume of 2.69 g of water at this temperature? V= mL

Explanation:

Density can be found using the following formula:

Rearrange the formula for v. Multiply both sides by v, then divide both sides by d.

The volume can be found by dividing the mass by the density. The mass is 2.69 grams and the density is 0.992 grams per milliliter.

Substitute the values into the formula.

Divide. Note that the grams, or g, will cancel each other out.

The volume of the water is 2.71169355 milliliters.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%