What is the pOH of a 0.011 M HI solution? a. 9.49
b. 4.51
с. 15.96
d. 1.96
e. 12.04

Option E. 12.04

Explanation:

We begin by calculating the hydrogen ion concentration, [H+] in the solution. This can be obtained as follow:

HI will dissociate in solution as follow:

HI (aq) —> H+(aq) + I-(aq)

From the above equation,

1 mole of HI produced 1 mole of H+.

Therefore, 0.011 M HI solution will also produce 0.011 M H+ solution.

Therefore, the hydrogen ion concentration, [H+] in the solution is 0.011 M

Next, we shall determine the pH of the solution. This can be obtained as follow:

Hydrogen ion concentration, [H+] = 0.011 M

pH =?

pH = – Log [H+]

pH = – Log 0.011

pH = 1.96

Finally, we shall determine the pOH of the solution as follow:

pH = 1.96

pOH =?

pH + pOH = 14

1.96 + pOH = 14

Collect like terms

pOH = 14 – 1.96

pOH = 12.04

Therefore, the pOH of the solution is 12.04

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