Does the chemical reaction presented in the data table follow the law of conservation of matter? Justify your answer with evidence from the
document.

No, it does not follow

Explanation:

The law of consevation of matter states that matter can neither be created nor destroyed. Hence, in a closed system involving a physical or chemical reaction, the amount of matter (mass) present in the reactants must equate the amount of matter in the products.

i.e. mass of reactants = mass of products

In the chemical reaction in the image, sodium reacts with hydrogen chloride (reactants) to give sodium chloride and hydrogen gas (products). That is,

Na(s) + HCl(aq) > NaCl(aq) + H2(g)

According to the image, the mass of Na= 14.25g, HCl= 9.50g, {NaCl + H2} = 22.98g

The mass of the reactants is 14.25+9.50= 23.75g

Mass of products= 22.98g

The mass of reactants and products are not equal and hence, does not follow the law of conservation of matter.

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

hope this mark me brainliest