How many calories are required to convert 2 grams of ice at 0 degrees C to water vapor at 100 degrees C?

360.8987 GRAM CALORIE OR 0.3608987 KILOCALORIE IS THE CALORIE REQUIRED TO CONVERT 2 GRAMS OF ICE AT 0 DEGREES C TO WATER VAPOUR AT 100 DEGREES C.

Explanation:

To convert 2 g of ice at 0 C to water vapor at 100 C:

First, the ice will be converted to water at 0 C

Then, water at 0 C to water vapor at 100 C

We must know that the latent heat of fusion for ice is 3.35*10^5 J/kg

the standard heat of enthalpy of water = 4200 J/kg

So therefore

Total heat to convert ice at 0 c to water vapor at 100 c is:

= M Lf + mc Q

= 2/ 1000 * 3.35 * 10^5 + 2/1000 * 4200 * (100 -0)

= 0.002 * 3.35 ^ 10^5 + 0.002 * 4200 * 100

= 0.0067 * 10 ^5 + 840

= 670 + 840

= 1510 J

The heat required to convert 2 g of ice at 0 c to water vapor at 100 C is 1510 J and to get the calorie value we divide the answer in joules by 4.184.

1510 joules = 360.8987 gram calories or 0.3608987 kilocalorie.

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