Can someone please help me w these chemistry conversion? 1. The density of Mercury is 13.6 g/mL. What is the volume of mercury, in quarts has a mass of 95.0 ounces? 2. Tetrachloroethylene, also called PERC, has a density of 1.62 g/mL. It was formerly used as a dry cleaning solvent. What is the mass in pounds of PERC contained in a 55.0 gallon drum? 3. Osmium is the most dense element having a density of 22.5 g/cm^3 Calculate the density of osmium in kg/m^3. 4. The density of Iron is 7.50 g/cm^3. What is the mass, in pounds, of a cube of iron that measures 5.00 cm on a side? 5. Lead has a density of 10.5 g/cm^3. What is the diameter of a lead ball that has a mass of 500.0 g? Report answer in cm.

1. 0.209quart

2. 743.6pounds

3. 22500kg/m^3

4. 2.07pounds

5. 4.50cm

Explanation:

Note that, these questions are related to density which can be calculated using the formula:

Density (p) = Mass (m) / Volume (v)

However, the units are different for each questions, hence, must be made the same

1. 1 ounce = 28.35 grams

95 ounces will be 95 × 28.35 = 2693.2g

Volume = mass/density

Volume of Mercury= 2693.2/13.6

Volume= 198ml

1 ml = 0.00106quart

198ml = 198 × 0.00106 = 0.209quart

2. 1 gallon = 3785.4ml

55 gallons = 55× 3785.4 = 208197ml

Mass = density × volume

Mass = 1.62 × 208197

Mass = 337,279.14g

1 pounds = 453.592 g

337279.14 g = 337279.14/453.592

Mass = 743.6pounds

3. 1g/cm^3 = 1000kg/m^3

Hence, a density of 22.5g/cm^3 will be 22.5 × 1000 = 22500kg/m^3

4. Volume of a cube of side 5cm each will be 5×5×5 = 125cm^3

Density = 7.50g/cm^3

Mass = Density×volume

Mass in grams = 7.50 × 125

Mass = 937.5grams

1 pound = 453.592 g

Therefore, 937.5g will be 937.5/453.592 = 2.07pounds.

5. Volume = Mass / density

Volume = 500/10.5

Volume = 47.62cm^3

Since a ball is spherical in shape, volume of a sphere (V) = 4/3πr^3

To find radius, we say;

47.62 = 1.33 × 3.142 × r^3

47.62 = 4.179 × r^3

r^3 = 47.62/4.179

r^3 = 11.395

r = 3√11.395

r = 2.25cm

To get diameter (d), we multiply the radius (r) by 2,

d = 2 × 2.25

d= 4.50cm

astronomers such as edwin hubble.

a c d and f

just finished the assignment