It is possible to make a buffer that functions well near pH 7 using citric acid, which contains only carboxylate groups. Explain. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. a. decreaseb. increasec. repulsionsd. associatese. attractionsf. dissociate1. Successive deprotonationsthe (−) charge density on the resulting anion.2.This results in unfavorable electrostaticbetween the carboxylate anions, which reduces the likelihood that a proton would.3. It is more favorable for the proton to remain bound to reduce unfavorable charge.

Complete Question

it is possible to make a buffer that functions well near pH 7 using citric acid, which contains only carboxylate groups. Explain. Drag the terms on the left to the appropriate blanks on the right to complete the sentences.

Words : decrease, increase, repulsion, associates, attractions, dissociate

1. Successive deprotonations the (−) charge density on the resulting anion.

2.This results in unfavorable electrostatic between the carboxylate anions, which reduces the likelihood that a proton would

3.it is more favorable for the proton to remain bound to reduce unfavorable charge . .

1

Successive deprotonations increase the (−) charge density on the resulting anion.

2

This results in unfavorable electrostatic repulsion between the carboxylate anions, which reduces the likelihood that a proton would dissociate

3

It is more favorable for the proton to remain bound to reduce unfavorable charge repulsion

Explanation:

Generally

Successive deprotonations decrease the (−) charge density on the resulting anion.

This because deprotonations means removal of positive charge

This results in unfavorable electrostatic repulsion between the carboxylate anions, which reduces the likelihood that a proton would dissociate

It is more favorable for the proton to remain bound to reduce unfavorable charge repulsion

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

pv=nrt

explanation: