For the following, identify the most likely value for x. a. BHx b. CHx c. NHx d. CH2Clx

Given :

a. b. c. d. .

To Find :

Find the most likely vale of x for each one .

Solution :

a .

Because boron have valency of 3 .

So , x = 3 .

b .

Valency of carbon is 4 .

x = 4 .

c .

Valency of nitrogen is 3 .

Therefore , x = 3 .

d .

Now ,we know valency of carbon is 4 and hydrogen is 1 .

Also , two hydrogen are already there .

So , only 2 electrons left to share .

Since , chlorine have valency of 1 .

Therefore , only 2 electrons of chlorine can connect .

x = 2 .

Hence , this is the required solution .

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