The element rubidium forms a with the charge . The symbol for this ion is , and the name is . The number of electrons in this ion is .

The element rubidium forms a cation with a charge of +1. The symbol of this ion is Rb+, and the name is rubidium ion. The number of electrons in this ion is 36 electrons

Explanation:

Rubidium belongs to the group 1A of the periodic table of elements. It is an alkali metal. The rubidium atom has an atomic number of 37. The neutral atom also has 37 electrons.

Being a metal, it forms ions by the loss of electrons. Since it is an alkali metal, it has one valence shell electron. It loses this one electron to form the rubidium ion, Rb+ which then has 36 electrons.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole