How many millimoles of Cr2O72- ions and K1+ ions are present in 483. mL of a 0.0750 M K2Cr2O7?1. mmolCr2O72- 2. mmol K1+

72.45 mmol K⁺ and 36.225 mmol Cr₂O₇²⁻

Explanation:

It is possible to obtain millimoles of a substantce by the multiplication of molarity times milliliters of the solution.

In the solution that is 0.0750M K₂Cr₂O₇:

K⁺ = 0.0750M * 2 = 0.150M

Cr₂O₇²⁻ = 0.0750M

The millimoles of these ions are:

Millimoles K⁺:

483mL * 0.150M = 72.45 mmol K⁺

Millimoles Cr₂O₇²⁻:

483mL * 0.075M  = 36.225 mmol Cr₂O₇²⁻

in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.