A medium-sized banana (118g) on average contains 422 mg of potassium - a nutrient needed to maintain fluid balance. If someone eats a medium-sized banana each day for a week, how many total grams of potassium are ingested in that week?

2.954 g

Explanation:

One banana contains 422 mg

One banana weighs 118 g

To make our calculations easier, we will convert both unit to the same power, that is both of them will be in g.

422 mg = 422/1000 = 0.422 g

If one banana contains 0.422 g of potassium, then 7 bananas(since he eats 1 per day) will weigh

0.422 * 7 = 2.954 g

Thus, after a week, he would have ingested at least 2.954 g of potassium.

I hope you understand the explanations. Thanks

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%