What is the concentration of OH− and pOH in a 0.00072 M solution of Ba(OH)2 at 25 ∘C? Assume complete dissociation.

Given :

0.00072 M solution of at .

To Find :

The concentration of and pOH .

Solution :

1 mole of gives 2 moles of ions .

So , 0.00072 M mole of gives :

Now , pOH is given by :

Hence , this is the required solution .

i believe it is c.) 1575 j.

what is the question here. i think you messed up.