G A sample of chlorine gas occupies 1550 mL at 0.945 atm and 50 C. What is the mass of the sample

THE MASS OF THE SAMPLE IS 25.37 g

Explanation:

Using PV = m RT / Mm

P = 0.945 atm

V = 1550 mL = 1.55 L

R = 0.082

T = 50 C

m = unknown

Mm = molar mass = 35.5 * 2 = 71 g/mol

Re-arranging the formula by making m the subject of the equation, we have:

m = PV Mm / RT

m = 0.945 * 1.55 * 71 / 0.082 * 50

m = 103.99725 / 4.1

m = 25.37 g

The mass of the sample is therefore 25.37 g

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.