A rigid container of O 2 has a pressure of 355 kPa at a temperature of 619 K. What is thepressure at 253 K?

130.2kPa

Explanation:

According to Gay-Lussac's Law:

P

∝

T

.

It follows that

P

=

k

T

, and so:

P

T

=

k

. It means that we can also say:

P

1

T

1

=

P

2

T

2

We need to find

P

2

. Rearranging to solve for such:

P

2

=

P

1

T

2

T

1

We know that:

P

1

=

340

kPa

T

1

=

713

K

T

2

=

273

K

Inputting:

P

2

=

340

⋅

273

713

P

2

=

130.2

kPa

is the new pressure

it should be all of them because it asks if you included all of those in your answer

explanation:

i believe the answer is a.