What is the mass of an rock that has a density of 3.52 g/cc. and when put in a graduated cylinder with 50ml of water makes the level rise to 62ml.

The mass of the rock is 42.24 g

We'll begin by calculating the the volume of the rock.

Volume of rock = (Volume of water + rock) – (Volume of water)

Volume of rock = 62 – 50

Volume of rock = 12 mL

Finally, we shall determine the mass of the rock.

Mass of rock =?

Mass = Density × Volume

Mass of rock = 3.52 × 12

Mass of rock = 42.24 g

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m = 42.24 grams

Explanation:

Given that,

The density of the mass of a rock is 3.52 g/cm³.

Initial volume of the graduated cylinder is 50 mL and when rock is put in it the water level makes the level rise to 62 mL.

We need to find the mass of the rock.

Volume of rock = final volume - initial volume

Volume of rock = 62 mL - 50 mL

Volume of rock = 12 mL

1 ml = 1 cm³

So, 12 mL = 12 cm³

Density=mass/volume

So, the mass of the rock is 42.24 grams.

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

it is a solid

explanation: