A sample of 2.00 mol of gas in a 10.00 L container is at 45.0 °C. What is the pressure (in atm) of the gas?

5.22 atm

Explanation:

The following data were obtained from the question:

Number of mole (n) = 2 moles

Volume (V) = 10 L

Temperature (T) = 45 °C

Pressure (P) =?

Next, we shall convert 45 °C to Kelvin temperature. This can be obtained as follow:

Temperature (K) = Temperature (°C) + 273

T (K) = T (°C) + 273

T (°C) = 45 °C

T(K) = 45 °C + 273

T (K) = 318 K

Finally, we shall determine the pressure of the gas by using the ideal gas equation as shown below:

Number of mole (n) = 2 moles

Volume (V) = 10 L

Temperature (T) = 318 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =.?

PV = nRT

P x 10 = 2 x 0.0821 x 318

Divide both side by 10

P = (2 x 0.0821 x 318) /10

P = 5.22 atm

Therefore, the pressure of the gas is 5.22 atm

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.

ill try to . no promises tho.

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