In an experiment, calcium carbonate reacted with different volumes of hydrochloric acid in water. One of the products formed during the experiment was carbon dioxide. The time taken for 0.89 mL of carbon dioxide to form was recorded. A partial record of the experiment is shown. Experimental Record Flask Mass of Calcium Carbonate Volume of HCl Volume of Water Time 1 4.0 g 25 mL 0 mL 11.2 seconds 2 4.0 g 20 mL 5 mL 3 4.0 g 15 mL 10 mL 4 4.0 g 10 mL 15 mL

12.8seconds, 14.6seconds, 16.4seconds

Explanation:

the answers should b right as long as it is increasing in trend.

the reason why is bc of lower vol of hcl, and higher vol of water present. there is amount of hcl molecules present per volume. lesser chance of collisions, lower rate of successful collisions to poduce CO2

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

the answer is c i took the test