Larissa needs to make 500ml of 2.00 M NaCl. The molecular weight of NaCl is 58.44. How does she make 500ml of 2.00 M NaCl? Question 3 options: A) Measure 29.22g NaCl and dissolve it into 500ml water. B) Measure 29.22g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask. C) Measure 58.44g NaCl and dissolve it into 500ml of water. D) Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.

D) Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.

Explanation:

Step 1: Given data

Molarity (M): 2.00 M

Volume (V): 500 mL = 0.500 L

Molar mass of NaCl: 58.44 g/mol

Step 2: Calculate the required moles of NaCl

We will use the following expression.

n = M × V

n = 2.00 mol/L × 0.500 L

n = 1.00 mol

Step 3: Calculate the mass corresponding to 1.00 moles of NaCl

1.00 mol × 58.44 g/mol = 58.44 g

Step 4: Describe the procedure to prepare the solution

Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.