If the Earth is represented by a basketball placed mid-court, how far away should the object representing the Moon be placed?

The moon should be at 543 cm.

Explanation:

If according to scientists the distance from the earth to the moon is approximately 384400 km

.

The earth has a radius of 6371 km.

A basketball has a radius of 9 cm.  (Using a basketball of this radius as a reference)

With these data you can make a rule of 3:

The earth in centimeters has a radius of 6.371e+8 cm.

So: If the earth has a radius of 6.371e+8 cm and a distance to the moon of 384,400 km, what would the distance be if the earth had a radius of 9 cm?

6.371e+8 cm      :      9 cm

384400 km       :       X

X = (384400 km * 9 cm) / 6.371e+8 cm

X = 5.43e-3 km converting to centimeters would give that:

X = 543 cm

The moon should be at 543 cm from Earth.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.