D= 1.246g/cm3 /(1 +8.324x10^-5 K^-1 T) at what temp (K) will the density of this liquid equal 1.212 g/cm3

At 336.6K, the density of the liquid is 1.212g/cm³

Explanation:

The density change in a substance with the temperature. As general (But not always applicable) rule, the density decreases with the temperature.

A formula to find density of the liquid of the problem is:

Where D is density and T is absolute temperature (In K).

If we want a density of 1.212g/cm^3:

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"