Perform the following mathematical operations and express each result to the correct number of significant figures. a. 97.381 ÷ 4.2502 + 0.99195 b. 171.5 + 72.915 – 8.23 c. 1.00914 ÷ 0.87104 + 1.2012 d. 21.901 – 13.21 – 4.0215

The answer is below

Explanation:

When estimating significant numbers, the following applies:

i) All non zero digits are significant

ii) Zeros before non zero digits are not significant

iii) Zeros placed between non zero digits are significant

iv) Trailing zeros to the right of decimals or trailing zeros in whole number are significant.

When estimating, we use the number with the highest number of significant figure.

a)  97.381 ÷ 4.2502 + 0.99195

=22.912098 + 0.99195 = 23.90405 to 5 s.f

b)  171.5 + 72.915 – 8.23    (72.915 has 5 s.f)

= 236.185 to 3 s.f

c)  1.00914 ÷ 0.87104 + 1.2012        (1.00914 has 6 s.f)

= 2.35975 to 6 s.f

d) 21.901 – 13.21 – 4.0215     (21.901 has 5 s.f)

= 4.4895 to 5 s.f

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weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.