In which list are the three compounds above correctly listed in order of increasing boiling point? A) lowest b. p isopropanol < isobutane < acetone ...highest b. p. B) lowest b. p isobutane < acetone < isopropanol ...highest b. p. C) lowest b. p isobutane < isopropanol < acetone ...highest b. p. D) lowest b. p acetone < isobutane < isopropanol ...highest b. p. E) lowest b. p acetone < isopropanol < isobutane ...highest b. p.

The correct answer is - option B -  lowest b.p isobutane < acetone < isopropanol ...highest b.p.

Explanation:

Isobutane has lowest boiling point due to no hydrogen bonding and no diole to dipole interaction found in them. Isobutane only shows weak dispersion force.

Acetone has dipole dipole interaction but due to lack of Hydrogen bonding they have low boiling point than isopropanol but higher than isobutanol.

Isopropanol is the compound that has ability to form hydrogen bonding with other molecule its boiling point is maximum among all three.

Thus, the correct answer is - option B -  lowest b.p isobutane < acetone < isopropanol ...highest b.p.

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.