the mass of empty cylinder is 20 gram its mass when its filled completely with water is 30 gram and its mass when its filled completely with unknown liquid is 27 gram find the density of, the unknown liquid

≈ 0.70 g/cm³ (answer rounded up to 2 decimal places)

Explanation:

The mass of empty cylinder is 20g

The mass of water filling the cylinder = 30g - 20g = 10g

The mass of unknown liquid filling the cylinder = 27g - 20g = 7g

Density of water = 997 kg/m³

Converting this density to g/cm³ we get;

1kg = 1000g , 1m³ = 1000000cm³

So density = g/cm³ = 0.997 g/cm³

So the volume of water occupied by 10g is;

10 × 0.997 = 9.97 cm³

This volume is also occupied by 7g of the unknown liquid.

Density = mass/volume

Density of the unknown liquid = 7g ÷ 9.97cm³ = 0.702106319 g/cm³ ≈ 0.70 g/cm³ (answer rounded up to 2 decimal places)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole