We put 10.0 moles of N2O into a 2.0 L container at some temperature. At equilibrium, 2.20 moles of N2 remain. Calculate the equilibrium constant, Kc, for the reaction at this temperature. 2N2O(g) "yields" 2N2(g) + O2(g)

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.