A student mixed 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH in a coffee cup calorimeter and calculate the molar enthalpy change of the acid-base neutralization reaction to be –54 kJ/mol. He next tried the same experiment with 100 ml of 1.0 M HCl and 100 ml of 1.0 M NaOH. The calculated molar enthalpy change of reaction for his second trial was:

The calculated molar enthalpy change of reaction for his second trial was -108 kJ.

Explanation:-

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Thus

Thus

Given for second trial:

0.05 moles of reacts with 0.05 moles of to release  heat = 54 kJ

0.1 moles of reacts with 0.05 moles of to release  heat  =

Thus calculated molar enthalpy change of reaction for his second trial was -108 kJ.

i think its 100.

hope this !