Chemistry, 12.08.2020 06:01, twiddleturd
The molar solubility of a salt with the formula YoDa where Yo has a charge of +2 is equal to 2.5 × 10-5 mol/L. Calculate the Ksp for YoDa. Report your answer to the tenths place and use scientific notation (e. g., 1.2e-8 or 1.2E-8).
Answers: 2
Chemistry, 21.06.2019 16:30, KieraKimball
10-14. (a) when 100.0 ml of weak acid ha were titrated with 0.093 81 m naoh, 27.63 ml were required to reach the equivalence point. find the molarity of ha. (b) what is the formal concentration of a- at the equivalence point? (c) the ph at the equivalence point was 10.99. find pk. for ha. (d) what was the ph when only 19.47 ml of naoh had been added?
Answers: 1
Chemistry, 21.06.2019 22:00, applereams
If a plot weight (in g) vs. volume (in ml) for a metal gave the equation y= 13.41x and r^2=0.9981 what is the density of the metal?
Answers: 2
Chemistry, 22.06.2019 02:20, kristieroth1
Compared with the freezing-point depression of a 0.01 m c6h12o6 solution, the freezing-point depression of a 0.01 m nacl solution is
Answers: 1
The molar solubility of a salt with the formula YoDa where Yo has a charge of +2 is equal to 2.5 × 1...
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