A tank originally had 12.0 atm, was 3.9L at 25C. If the tank is heated to 591C what is the new pressure ?

34.79 atm.

Explanation:

The following data were obtained from the question:

Initial pressure (P1) = 12 atm

Initial temperature (T1) = 25 °C

Final temperature (T2) = 591 °C

Final pressure (P2) =...?

Note: the volume of the tank is constant.

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

Temperature (K) = Temperature (°C) + 273

T(K) = T (°C) + 273

Initial temperature (T1) = 25 °C

Initial temperature (T1) = 25 °C + 273 = 298 K.

Final temperature (T2) = 591 °C

Final temperature (T2) = 591 °C + 273 = 864 K.

Finally, we shall determine the new pressure as follow:

Initial pressure (P1) = 12 atm

Initial temperature (T1) = 298 K.

Final temperature (T2) = 864 K.

Final pressure (P2) =...?

P1/T1 = P2/T2

12/298 = P2/864

Cross multiply

298 x P2 = 12 x 864

Divide both side by 298

P2 = (12 x 864)/298

P2 = 34.79 atm.

Therefore, the new pressure is 34.79 atm.