A container initially holds 5.67 x 10^10-2 mol of propane and has a volume of V1. The volume of the container was increased by adding an additional 2.95 x 10^-2 mol of propane to the container, so that the container has a final volume of 1.93 L. If the temperature and pressure are constant, what was the initial volume of the container ,V1?

The initial volume of the container was 1.27L

Explanation:

Avogadro's law states that under the same pressure and temperature, equal moles of gases occupies equal volume. The equation is:

V₁n₂ = V₂n₁

Where V is volume and n moles of 1, initial state and 2, final state.

In the problem, initial moles are 5.67x10⁻², final moles after the addition are:

5.67x10⁻² + 2.95x10⁻² = 8.62x10⁻² moles

And, after the addition, the volume is 1.93L.

Replacing in Avogadro's law:

V₁×8.62x10⁻² moles = 1.93L×5.67x10⁻² moles

V₁ = 1.27L

here are some of the ways in which chemical and nuclear reactions differ.

explanation:

4d^55s^1 ( third choice)