assume that amonia can be prepared by the folowing reaction in the gas phase at STP. If the reaction conditions are maintainted at STP, how many liters of NH3 can be produced by the reaction of 12.0 L of H2 and the exact required volumen of N2

8.00L of ammonia can be produced

Explanation:

The reaction is:

N₂(g) + 3H₂(g) → 2NH₃(g)

Where 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

Avogadro's law states that, under constant pressure and temperature, equal volumes of gases contains equal number of moles.

As in the reaction conditions are mantained at STP (Pressure and temperature are constant) you can say of the reaction that:

1 liter of nitrogen reacts with 3 liters of hydrogen to produce 2 liters of ammonia

Thus, if 12.0L of hydrogen reacts and 3L of hydrogen produce 2L of ammonia, liters of ammonia produced are:

12L H₂(g) ₓ (2L NH₃(g)  /  3L H₂(g)) =

thats a little if u want the answer just look it up on google thats what i do haha : )

the volume increases