Given the wavelength of the corresponding emission line, calculate the equivalent radiated energy from n = 4 to n = 2 in both joules and electron volts. Also, calculate the frequency of the wave. λ (Á) = 4861, ƒ(Hz), E(J), E(eV)

Explanation:

It is given that,

Initial orbit of electrons,

Final orbit of electrons,

We need to find energy, wavelength and frequency of the wave.

When atom make transition from one orbit to another, the energy of wave is given by :

Putting all the values we get :

We know that :

So,

Energy of wave in terms of frequency is given by :

Also,

is wavelength

So,

Hence, this is the required solution.

f(Hz) = 6.17 × 10¹⁴

E(J) = 4.09 × 10⁻¹⁹

E(ev) = 2.56

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the answer is 303.15 or 303