A roller coasters velocity at the top of a hill is 21mls. Two seconds later it reaches the bottom of the hill with a velocity of 36mls. What is the acceleration of the roller coasters

7.5 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 21 m/s

Final velocity (v) = 36 m/s

Time (t) = 2 secs

Acceleration (a) =..?

The acceleration of an object is simply defined as the rate of change of velocity of the object with time. Mathematically, it is represented as:

Acceleration (a) = (final velocity (v) – initial velocity (u)) / time (t)

a = (v – u)/t

With the above formula, we can determine the acceleration of the roller coaster as follow:

a = (v – u)/t

a = (36 – 21)/2

a = 15/2

a = 7.5 m/s²

Therefore, the acceleration of the roller coaster is 7.5 m/s².

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

14 days is the half-life of phosphorus-32