Chemistry, 29.07.2020 04:01, kimbyrleeclark
The original red stock solution has the same concentration as the green stock solution since one mole of the red aquo complex forms for each mole of the green chloro complex that is converted. Therefore, the concentrations of the two sets of four diluted solutions, the red and green, are equal for each respective concentration. Enter them in decreasing order (highest to lowest) of concentration in units of moles per liter. Enter your molarities using 3 significant figures, i. e. 0.00875 M.
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Chemistry, 22.06.2019 03:50, AysiaRamosLee
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Chemistry, 22.06.2019 07:50, carlosiscr7
Many reactions take place in aqueous solution. when potential reactants are mixed, a reaction will occur if there is some driving force that favors the formation of products. it is often convenient to categorize reactions in terms of these driving forces: precipitate formation, in which an insoluble solid is formed, weak electrolyte formation, as in a neutralization reaction involving water, or transfer of electrons, as in a redox reaction. these reactions can be represented by full molecular equations, which contain all species in the reaction mixture, or by net ionic equations, which show only the species that actually undergo a change. the latter does not contain the spectator ions, which do not undergo a net change or do not take part in the reaction. part a when the following two solutions are mixed: k2co3(aq)+fe(no3)3(aq) the mixture contains the ions listed below. sort these species into spectator ions and ions that react. drag the appropriate items to their respective bins. view available hint(s) spectator ions ions that react part b what is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants? assume that the contribution of protons from h2so4 is near 100 %.ba(oh)2(aq)+h2so4(aq)→ express your answer as a chemical equation. view available hint(s) nothing provide feedback
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The original red stock solution has the same concentration as the green stock solution since one mol...
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