The vapor pressure of methanol is 143 mmhg. identify the best reason to explain why methanol spontaneously evaporates in open air at 25.0∘c and standard pressure (760 mmhg). the vapor pressure of methanol is 143 . identify the best reason to explain why methanol spontaneously evaporates in open air at 25.0 and standard pressure (760 ). under these nonstandard conditions, the partial pressure of methanol is lower than its vapor pressure. calculations for a closed container show a partial pressure of methanol lower than its vapor pressure. the calculated standard free energy change corresponds to a spontaneous reaction. heat can be added under these nonstandard conditions to increase the vapor pressure of methanol.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

hypostyle hall;