In the reaction below green chlorine gas and brown iodine chloride forms yellow iodine trichloride
Cl2 (g) + ICI () = IC13 (s)
If some chlorine is removed from the reaction, how will
it affect the color of the mixture?
A. It will become more green.
B. It will become more yellow.
C. It will become more brown.
OD. It will not change.

The correct option is;

C. It will become more brown

Explanation:

Given that the reaction is as follows;

Cl₂(g) + ICl (g) ⇄ ICl₃

We have that the reaction and a decrease in the concentration of the reactants will favor the reverse reaction that is the decomposition of the yellow iodine trichloride and the formation of green chlorine gas and brown iodine chloride

Given that some green chlorine gas, which is part of the reactant, will be removed, the reverse reaction will be favored and initial concentration of the yellow iodine trichloride and the green chlorine gas will be reduced while the proportional concentration of the brown iodine chloride will increase and the mixture will become more brown.

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

it is the most commonly accepted one