The volume of a sample of pure HCl gas was 221 mL at 20°C and 111 mmHg. It was completely dissolved in about 50 mL of water and titrated with an NaOH solution; 18.7 mL of the NaOH solution was required to neutralize the HCl. Calculate the molarity of the NaOH solution.

Explanation:

We know that , the reaction of HCl and NaOH is given as follows

Given that

Pressure = 111 mm Hg

Temperature = 20°C

T=20+273=293 K

Volume= 221 m L

V=0.221 L

Number of moles of HCl is given as follows

From the above reaction we can say that

Number of moles of HCl=Number of moles of NaOH

Volume of NaoH is given as follows

V=18.7 = 0.0187 L

Therefore molarity

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.