a 2.000-g sample of a hydrated copper sulfate is heated and the waters of hydration are removed if that mass of the remaining salt is 1.278 g what was the percentage of water in the original hydrate

36.1%

Explanation:

The following data were obtained from the question:

Mass of hydrated copper sulfate = 2 g

Mass of anhydrous copper sulfate = 1.278 g

Percentage of water =..?

Next, we shall determine the mass of water in the hydrated copper sulfate.

This can be obtained as follow:

Mass of hydrated copper sulfate = 2 g

Mass of anhydrous copper sulfate = 1.278 g

Mass of water =...?

Mass of water = Mass of hydrated copper sulfate – Mass of anhydrous copper sulfate

Mass of water = 2 – 1.278

Mass of water = 0.722 g

Finally, we can obtain the percentage of water in the hydrated copper sulfate as follow:

Mass of water = 0.722 g

Mass of hydrated copper sulfate = 2 g

Percentage of water =..?

Percentage of water = mass of water /mass of hydrate x 100

Percentage of water = 0.722/2 x 100

Percentage of water = 36.1%

Therefore, the percentage of water in the hydrated copper sulfate is 36.1%

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

the answers would be

the first one and the second one