Chemistry, 23.07.2020 18:01, Isactuallycarter99

Data Trial 1 Trial 2 Mass of empty crucible with lid (t1)26.688g (t2)26.692g Mass of Mg metal, crucible, and lid (t1)27.052g (t2)27.052g Mass of MgO, crucible, and lid (t1)27.285g (t2)27.282g Calculations: Show your calculations for each of the following. Remember, calculations should follow rules for significant figures.

1. Write the balanced chemical equation for the reaction you are performing.

2. Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of Mg, crucible, and lid (row 2 in the chart) to find the mass of magnesium for each trial. • Trial 1: 0.364 • Trial 2: 0.36
3. Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of MgO, crucible, and lid (row 3 in the chart) to find the mass of magnesium oxide for each trial. This is the actual yield of magnesium oxide for each trial.
• Trial 1: 0.597
• Trial 2: 0.59

4. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
• Trial 1:
• Trial 2:
5. Determine the percent yield of MgO for your experiment for each trial.
• Trial 1:
• Trial 2:

6. Determine the average percent yield of MgO for the two trials.

Answers: 3

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Data Trial 1 Trial 2 Mass of empty crucible with lid (t1)26.688g (t2)26.692g Mass of Mg metal, cruci...