What is the mole ratio of water to H3PO4?

Explanation:

Phosphoric acid H₃PO₄ is produced from reaction of water and tetraphosphorus decoxide  P₄O₁₀ as follows

P₄O₁₀ + 6 H₂O = 4 H₃PO₄

In this reaction 6 molecules of H₂O and one molecule of  phosphorus compound P₄O₁₀ is needed to produce phosphoric acid , ie the conversion factor of water to acid is 6 / 1

This ratio is called mole ratio of water to H₃PO₄.

So the required ratio is 6 : 1 .

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.